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Unverified Commit 47d3df82 authored by rrueger's avatar rrueger
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Algebra I: Modules. Update clarity on corollary

parent 2aa5070e
......@@ -99,9 +99,12 @@ Evidently, this homomorphism is surjective and we have $M = Rx \cong R/\ker
Let $M = Rx$ be a cyclic $R$-module. Then we have
Rx \cong R /\ann x
by the first isomorphism theorem.
\begin{theorem}[Existence of a Base]
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